Crud operation : filter, delete, and update element in Array
Crud operation : filter, delete, and update element in Array
The code you provided seems to define an array of products and a few operations to filter, delete, and update them. However, there are a couple of things to address:
-
updateproductsfunction:- The
updateproductsfunction currently has a small issue. You are trying to returnfalsefor the products that do not match the specifiedname, which can result in an array offalsevalues for the non-matching items. Instead, you should return the non-matching items unchanged. Otherwise, you would be removing them from the result. You should return the original product when it doesn't match thename.
- The
-
deleteproductsfunction: splicemutates the original array, removing elements in place, so this will change theproductsarray directly. This can lead to unexpected behavior if you're trying to maintain the original array in subsequent operations. If you want to avoid modifying the original array, you could create a copy of it first.Your code is almost correct, but there are a couple of issues, especially with the usage of
reduceand how you're calculating the total price. Let's go over each section:1.
mapimplementation:You're trying to use
mapto accumulate the total price intotalprice, but this approach is not quite ideal becausemapis designed to return a new array, not for side effects like accumulation. You can still usemapif you'd like, but it's not the most appropriate method here.2.
reduceimplementation:In the
reducefunction, you're trying to addaccum.priceandcurElem.price. The issue is thataccumis an accumulator, which starts as a number (0 in this case). So,accum.pricewill cause an error sinceaccumis not an object.Here's the corrected version of your code:
Explanation:
-
mapmethod:- You are using
mapto accumulate the total price, but it's better to usereducefor accumulation becausemapis meant to transform an array into a new array. - The result
r[r.length - 1]is correct to get the final accumulated price, but this is not a standard use case formap.
- You are using
-
reducemethod:- The
reducefunction is ideal for accumulation. It takes two arguments:accum: The accumulator (starts with0).curElem: The current element being processed.
- The expression
accum + curElem.pricesums the prices of all products. You don't need to accessaccum.price, becauseaccumis just a number here.
- The
-
Here is a code with these improvements:
let products = [{ name: "laptop", price: 1200 },{ name: "phone", price: 800 },{ name: "tablet", price: 300 },{ name: "smartwatch", price: 150 },]console.log(products);const filterproducts = (data) => {return data.filter(item => { return item.price <= 500 });}const deleteproducts = (data) => {return data.splice(0, 2);}const updateproducts = (name) => {return products.map((item) => {if (item.name == name) {return { name: "smart", price: 100, status: true };} else {return false;}})}// console.log(filterproducts(products));// deleteproducts(products);console.log(updateproducts("laptop"));console.log(products);// Using map (not recommended for accumulating totals, but works)let totalprice = 0;let r = products.map((item, id) => {totalprice += item.price;return totalprice;});console.log(r[r.length - 1]); // The last value in the array is the total price// Correct way using reduce to calculate total price of productsconst total = products.reduce((accum, curElem) => {return accum + curElem.price; // Just sum the prices}, 0);console.log(total); // Output total price using reduce
Changes:
- In
updateproducts, if a product name matches, it is updated, but the non-matching items are kept unchanged. - In
deleteproducts, I replacedsplicewithslice, which creates a new array without mutating the original array. You could usespliceif mutation is acceptable, but it directly changes theproductsarray. - The
console.logstatements show the changes or original array states.
Now, you can run the code and see how it behaves. Here's a quick summary:
- The
filterproductsfunction will return items with a price less than or equal to 500. - The
deleteproductsfunction will delete the first two products and return a new array. - The
updateproductsfunction will update the product matching the given name and leave the others unchanged.
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